Integrand size = 25, antiderivative size = 103 \[ \int \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2 \, dx=\frac {10 a b \sqrt {d \sec (e+f x)}}{3 f}+\frac {2 \left (3 a^2-2 b^2\right ) \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right ) \sqrt {d \sec (e+f x)}}{3 f}+\frac {2 b \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}{3 f} \]
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Time = 0.16 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {3589, 3567, 3856, 2720} \[ \int \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2 \, dx=\frac {2 \left (3 a^2-2 b^2\right ) \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right ) \sqrt {d \sec (e+f x)}}{3 f}+\frac {10 a b \sqrt {d \sec (e+f x)}}{3 f}+\frac {2 b \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}{3 f} \]
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Rule 2720
Rule 3567
Rule 3589
Rule 3856
Rubi steps \begin{align*} \text {integral}& = \frac {2 b \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}{3 f}+\frac {2}{3} \int \sqrt {d \sec (e+f x)} \left (\frac {3 a^2}{2}-b^2+\frac {5}{2} a b \tan (e+f x)\right ) \, dx \\ & = \frac {10 a b \sqrt {d \sec (e+f x)}}{3 f}+\frac {2 b \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}{3 f}+\frac {1}{3} \left (3 a^2-2 b^2\right ) \int \sqrt {d \sec (e+f x)} \, dx \\ & = \frac {10 a b \sqrt {d \sec (e+f x)}}{3 f}+\frac {2 b \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}{3 f}+\frac {1}{3} \left (\left (3 a^2-2 b^2\right ) \sqrt {\cos (e+f x)} \sqrt {d \sec (e+f x)}\right ) \int \frac {1}{\sqrt {\cos (e+f x)}} \, dx \\ & = \frac {10 a b \sqrt {d \sec (e+f x)}}{3 f}+\frac {2 \left (3 a^2-2 b^2\right ) \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right ) \sqrt {d \sec (e+f x)}}{3 f}+\frac {2 b \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}{3 f} \\ \end{align*}
Time = 1.65 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.84 \[ \int \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2 \, dx=\frac {2 \sec ^2(e+f x) \sqrt {d \sec (e+f x)} \left (\left (3 a^2-2 b^2\right ) \cos ^{\frac {5}{2}}(e+f x) \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right )+b \cos (e+f x) (6 a \cos (e+f x)+b \sin (e+f x))\right )}{3 f} \]
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Result contains complex when optimal does not.
Time = 15.54 (sec) , antiderivative size = 239, normalized size of antiderivative = 2.32
method | result | size |
parts | \(-\frac {2 i a^{2} \left (\cos \left (f x +e \right )+1\right ) F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {d \sec \left (f x +e \right )}\, \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}}{f}+\frac {2 b^{2} \sqrt {d \sec \left (f x +e \right )}\, \left (2 i \cos \left (f x +e \right ) F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}+2 i \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}+\tan \left (f x +e \right )\right )}{3 f}+\frac {4 a b \sqrt {d \sec \left (f x +e \right )}}{f}\) | \(239\) |
default | \(-\frac {2 \sqrt {d \sec \left (f x +e \right )}\, \left (3 i \cos \left (f x +e \right ) F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, a^{2}-2 i \cos \left (f x +e \right ) F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, b^{2}+3 i \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) a^{2}-2 i \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) b^{2}-6 a b -\tan \left (f x +e \right ) b^{2}\right )}{3 f}\) | \(276\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.09 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.29 \[ \int \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2 \, dx=\frac {\sqrt {2} {\left (-3 i \, a^{2} + 2 i \, b^{2}\right )} \sqrt {d} \cos \left (f x + e\right ) {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right ) + \sqrt {2} {\left (3 i \, a^{2} - 2 i \, b^{2}\right )} \sqrt {d} \cos \left (f x + e\right ) {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right ) + 2 \, {\left (6 \, a b \cos \left (f x + e\right ) + b^{2} \sin \left (f x + e\right )\right )} \sqrt {\frac {d}{\cos \left (f x + e\right )}}}{3 \, f \cos \left (f x + e\right )} \]
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\[ \int \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2 \, dx=\int \sqrt {d \sec {\left (e + f x \right )}} \left (a + b \tan {\left (e + f x \right )}\right )^{2}\, dx \]
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\[ \int \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2 \, dx=\int { \sqrt {d \sec \left (f x + e\right )} {\left (b \tan \left (f x + e\right ) + a\right )}^{2} \,d x } \]
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\[ \int \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2 \, dx=\int { \sqrt {d \sec \left (f x + e\right )} {\left (b \tan \left (f x + e\right ) + a\right )}^{2} \,d x } \]
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Timed out. \[ \int \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2 \, dx=\int \sqrt {\frac {d}{\cos \left (e+f\,x\right )}}\,{\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )}^2 \,d x \]
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